Comments on: WPF DataGrid – Committing changes cell-by-cell

By: Jay R. Wren

Jay R. Wren — Tue, 28 Jun 2011 17:39:26 +0000

I found this a little bit better:

private IEditableObject rowBeingEdited = null;
private void dataGrid_CellEditEnding(object sender,
DataGridCellEditEndingEventArgs e)
{
DataRowView rowView = e.Row.Item as IEditableObject;
rowBeingEdited = rowView;
}

private void dataGrid_CurrentCellChanged(object sender, EventArgs e)
{
if (rowBeingEdited != null && dataGrid.CurrentCell.Item != rowBeingEdited)
{
rowBeingEdited.EndEdit();
}
}

This also addresses Michael’s concern about not deriving from DataRowView.

By: Jeremy

Jeremy — Fri, 17 Jun 2011 00:32:04 +0000

Now if invoking EndEdit() would cause my DataColumn expression to re-evaluate.

By: Colin Eberhardt

Colin Eberhardt — Mon, 24 May 2010 07:25:45 +0000

@gauss, nice one. Thanks for the link.

By: gauss

gauss — Thu, 20 May 2010 10:10:59 +0000

In the WPF Datagrid that was released with .net4.0 there is an easy way to commit the complete row on every cell edit regardless of what data is bound to it. Check out the code here: http://codefluff.blogspot.com/2010/05/commiting-bound-cell-changes.html

By: Colin Eberhardt

Colin Eberhardt — Sat, 08 May 2010 06:08:41 +0000

@rgames, you can find an answer to navigato’s question here:

http://social.msdn.microsoft.com/Forums/en/wpf/thread/c9a80fe6-cfca-4f5f-81d0-76c1ea3afa51

Basically, if you are not binding to a DataTable, you need to cast to your own type.

By: rgames

rgames — Fri, 07 May 2010 04:35:56 +0000

Same problem as navigato. Any help on that?

By: navigato

navigato — Mon, 25 Jan 2010 16:37:03 +0000

Hi Colin,

my “rowdata” is not derived from DataRowView Class and for that reason I always get “null” for rowView out of
DataRowView rowView = e.Row.Item as DataRowView;
And I’m not the only one with this problem as you can see here:
http://social.msdn.microsoft.com/Forums/en/wpf/thread/c9a80fe6-cfca-4f5f-81d0-76c1ea3afa51
Do you think there is a possibility to get a solution as simple as your one for the problem? Would be great to get an answer.

Michael

By: Colin Eberhardt

Colin Eberhardt — Wed, 16 Dec 2009 13:47:05 +0000

Glad to hear that it helped you

Colin E.